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Nuclear Equation using MathML
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${\mathrm{\&CapitalIota;}}_{0}\approx \frac{{R}_{\Lambda}}{4\Pi {D}^{2}}{e}^{-{\rm M}D}\phantom{\rule{3em}{0ex}}=\mathrm{\&FreakedSmiley;}$
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***I*_{0} is the radiation dose received at a distance
*D* from a nuclear explosion.
${R}_{\Lambda}\phantom{\rule{0.3em}{0ex}}\text{is the initial total radiation release, and}\phantom{\rule{0.3em}{0ex}}{\rm M}\phantom{\rule{0.3em}{0ex}}\text{is the attenuation factor in air. (e and}\phantom{\rule{0.3em}{0ex}}\Pi $
are mathematical constants).
*Ref: "The Effects Of Nuclear Weapons", US Dept. of Defense, April 1962,
section 8.98.*